Dernière suite du dm de maths 1er es svp

1) On a la formule Cm(q)=C(q+1)-C(q).

Ici C(q+1)=0.01(q+1)²+2(q+1)+1.5

C(q+1)=0.01q²+0.02q+0.01+2q+2+1,5

C(q+1)=0.01q²+2q+1.5+(0.02q+2.01)

d'où:

Cm(q)=0.02q+2.01.

2)C'(q)=0.02q+2

3)E(q)=0.02q+2-(0.02q+2.01)

E(q)=-0.01

4) Cm(q)=0.02q+2.01

donc Cm(1000)=0.02*1000+2.01=22.01.

E(1000)=-0.01 (ne dépend pas de q)