Je dois corriger ça pour demain, SVP aidez moi j'y arrive pas :( :(

Salut :

[tex]C = (x + \frac{2}{3})^{2} = x^{2} + 2*x* \frac{2}{3} + \frac{2}{3}^{2} = x^{2} + \frac{4}{3}x + \frac{4}{9} [/tex]
[tex]E = (x + 3)^{2} - 16 \\ E= x^{2} + 2*3*x + 3^{2} -16\\ E= x^{2} + 6x + 9 - 16 \\ E= x^{2} +6x -7[/tex]
[tex]B = (4x -3)^{2}- 9 \\ B = (4x)^{2} - 2 * 3 * 4x + 3^{2} -9 \\ B = 16x^{2} -12x + 9 - 9 \\ B = 16 x^{2} - 12x[/tex]

[tex]F = 25 x^{2} + 16 -40x \\ F = 25 x^{2} -40x+16 \\ F = (5x)^{2} - 2 * 4 * 5x + 4^{2} \\ F = (5x +4) x^{2} [/tex]
[tex]C = (2x - 3)^{2} - (3x + 2)(2x - 3) \\ C = 4 x^{2} - 12x + 9 - (6 x^{2} -9x + 4x -6) \\ C = 4 x^{2} -12x + 9 - 6 x^{2} +9x-4x+6 \\ C = -2 x^{2} -7x +15 [/tex]

[tex]D = 24 x^{2} +12 = 12(2x^{2} +1)[/tex]

(x+2/3)² = x²+4/3x+4/9

e/ (x+3)² -16 = x² +6x 9 -16 = x² +6x -7

(4x-3)² -9 = 16x² -12x + 9 - 9 = 16x² - 12x = 4x (4x-3)

d/ 81 -25 x²  pour info a² -b² =(a+b)(a-b) donc
(9-5x)(9+5x)

c/ desole je ne comprend pas ton enonce

24x²+12 = 12 (2x²+1)= 12 (x+1)²-2x